Finding the percentage of composition in the mixture

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SUMMARY

This discussion focuses on determining the percentage composition of a mixture containing magnesium carbonate (MgCO3) and calcium carbonate (CaCO3) using titration with sodium hydroxide (NaOH) to quantify remaining hydrochloric acid (HCl). The key steps involve calculating the moles of HCl that reacted with NaOH to infer the moles of HCl that reacted with the carbonate mixture. Participants emphasize the need to establish the relationship between the moles of MgCO3 and CaCO3, denoting them as x and y, respectively, to derive the total moles from titration results.

PREREQUISITES
  • Understanding of acid-base titration techniques
  • Knowledge of stoichiometry and mole calculations
  • Familiarity with chemical reactions involving carbonates and acids
  • Basic algebra for solving equations involving x and y
NEXT STEPS
  • Study the principles of acid-base titration using sodium hydroxide
  • Learn how to calculate moles from titration data
  • Explore stoichiometric relationships in chemical reactions
  • Investigate methods for determining the composition of mixtures in analytical chemistry
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in analytical chemistry or studying reaction stoichiometry will benefit from this discussion.

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Homework Statement
A mixture of calcium carbonate and magnesium carbonate weighs 2.36 g. It is dissolved in a 700 ml, 0.10 moles per cubic decimeter Hydrochloric solution. The resulting solution is then diluted up to 25 cubic decimeter with water. 20 ml of sodium hydroxide completely reacts with 25 ml of above prepared solution. Find the percentage composition of composition of the mixture.
Relevant Equations
C = n/v , C1V1=C2V2 , number of moles = mass/molar mass ..... I don't know what other equations appear here.
The thing is that, I don't know how to approach this question and the particular steps for relevant value findings. Please show me the path, and I will go in it friends. I couldn't attempt as I have no clue how to approach this. Thank you very much in advance.
 
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The titration with sodium hydroxide will tell you how much HCl remains in solution after reaction with the carbonate mixture. Therefore, a good starting point is to calculate how much HCl reacted with NaOH in the last step in order to infer how much HCl reacted with the carbonate mixture.
 
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Ygggdrasil said:
The titration with sodium hydroxide will tell you how much HCl remains in solution after reaction with the carbonate mixture. Therefore, a good starting point is to calculate how much HCl reacted with NaOH in the last step in order to infer how much HCl reacted with the carbonate mixture.

Yeah I did that, thank you very much. Hey are the number of moles of MgCO3 and number of moles of CaCO3 equal ? I could come to a solution but I don't know whether it is correct or not. Are the number of moles of the both equal?

What should I do after finding the excess amount of HCL present in the mixture that was diluted up to 25 dm3?
 
Targeting only for carbonate will not be enough information if you are looking for both how much Mg and how much Ca.
 
Assume x moles of magnesium carbonate and y moles of calcium carbonate.

Titration told you x+y.

Can you express sample mass with x, y?
 

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