Finding the point where the line of action intersect with r

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To find the intersection point of the line of action with CD, the discussion emphasizes the need to calculate moments and their relationship to torque. The equations for forces in the x and y directions are provided, with a resultant force of 991N. Participants question whether there are shortcuts to solve the problem or if trial and error is necessary. The importance of understanding the relationship between the moments of forces and the equivalent force's moment about point C is highlighted. A clear grasp of these concepts is essential for accurately determining the intersection point.
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Homework Statement


I'm having problem of finding the point where the line of action intersect with CD , hot to do it ?
Fx = -500cos60 - 250(4/5)
Fy = 300 + 500sin60 + 250(3/5)
FR = 991N

Homework Equations

The Attempt at a Solution

 

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What can you say about moments?
 
haruspex said:
What can you say about moments?
moment = rF r = perpendicular distance from the force... Is there any shortcut to do this question ? or just keep on trial and error until get the correct ans ??
 
Last edited:
werson tan said:
moment = rF r = perpendicular distance from the force... Is there any shortcut to do this question ? or just keep on trial and error until get the correct ans ??
No, I mean what is the relationship between the moments of the forces and torque in the diagram about C and the moment of the equivalent force?
 

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