Finding the radius of a charged metal sphere

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SUMMARY

The radius of the charged metal sphere is determined to be 0.623 m based on the given surface charge density of 24.6 nC/m² and the electric potential of 540 V at a distance of 2.00 m. The electric field strength of 270 V/m indicates that the charge on the sphere is positive, as the electric field points away from positively charged objects. This conclusion is drawn from the relationship between electric field direction and charge sign.

PREREQUISITES
  • Understanding of electric potential and electric field concepts
  • Familiarity with surface charge density calculations
  • Knowledge of Gauss's Law for electric fields
  • Basic algebra for solving equations related to electric properties
NEXT STEPS
  • Study Gauss's Law and its applications in electrostatics
  • Learn about the relationship between electric field and charge sign
  • Explore calculations involving electric potential in spherical charge distributions
  • Investigate the effects of varying surface charge densities on electric fields
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone interested in understanding the properties of charged objects and electric fields.

Jimmy25
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Homework Statement



A metal sphere centered at the origin has a surface charge density that has a magnitude of 24.6 nC/m2 and a radius less than 2.00 m. At a distance of 2.00 m from the origin, the electric potential is 540 V and the electric field strength is 270 V/m. (Assume the potential is zero very far from the sphere.)

1. What is the radius of the sphere?
2. Is the charge on the sphere positive or negative?

Homework Equations


The Attempt at a Solution



I found the radius as 0.623 m but how do I determine the sign of the charge on the sphere?
 
Last edited:
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shouldn't the electric field tell you the charge of the particle creating it
 

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