Finding the Range of the Function f(x)=x²+4: Interval Notation Explanation

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Homework Help Overview

The discussion revolves around finding the range of the function f(x) = x² + 4, with a focus on understanding interval notation. Participants are brushing up on concepts related to functions and their properties in a calculus context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the distinction between domain and range, with one participant attempting to clarify the range of the function. Questions arise regarding the correct interval notation for expressing the range.

Discussion Status

The discussion is active, with participants providing clarifications about the concepts of domain and range. Some guidance has been offered regarding the correct interval notation for the range, although there is no explicit consensus on the final answer yet.

Contextual Notes

There is a mention of confusion between domain and range, and participants are exploring the implications of interval notation in their explanations. The original poster is seeking a quick explanation, indicating a possible constraint on the depth of discussion.

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Find the range of the equation.
f(x)=x²+4Things I know for sure:
x²>=0

We are brushing up on functions and interval notation in my calc class, and I can't remember how to do this in interval notation. If x is a number being squared it has to be positive or zero. So at the minimum the answer is going to be:
f(x)=0+3

f(x)=3

So the interval notation would be what? Quick little explanation would help as well. Thanks.
 
Last edited:
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The domain of the function is all the possible inputs for your function. You seem to be looking at the range
 
You're right, that's what I meant. Good call. But what about interval notation?
 
Careful, I think you're confusing domain and range.

The range is [4,inf), the domain is (-inf,inf).

Basically the domain is a set of numbers that x can satisfy. For example g(x) = 1/x the domain is (-inf,0)U(0,inf) because g(x) is not defined at x=0.

The range is a set of numbers that your function can have as a value for a given domain of values. For example h(x) = x^2 has a range of [0,inf) since the minimum value of h(x) is 0 and the function will extend to infinity.

If a number is exclusive we use parenthesis, and if a number is inclusive we use brackets. So in the case of the domain of g(x) = 1/x, x cannot equal zero but it can approach the value of 0 so 0 is exclusive. Negative and positive infinity are always exclusive since they are not actual values. Therefore (-inf,0) is in parenthesis on both sides. But that's not the entire domain! We can have x>0 so we need to include that too. We write include (or union) with a capitol U so the answer is (-inf,0)U(0,inf).
 
Last edited:
Great, that helps a lot. Thanks.
 

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