Finding the remainder of an algebraic quotient

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SUMMARY

The discussion focuses on finding the remainder of the polynomial \(9x^{23} - 7x^{12} - 2x^{5} + 1\) when divided by \(x + 1\). The most efficient method highlighted is using the Remainder Theorem, which states that the remainder of a polynomial \(P(x)\) divided by \(x - r\) is \(P(r)\). In this case, substituting \(r = -1\) into the polynomial yields the remainder. This approach simplifies the process significantly compared to traditional long division.

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I'm tutoring a pupil for a CLEP exam and her book includes the following algebra problem:
What is the remainder when
<br /> 9x^{23} - 7x^{12} - 2x^{5} +1<br />
is divided by x+1?
I know how to find the answer by computing the quotient of these two expressions, but in this case doing that is so tedious I assume there's a more direct way of finding the remainder. What is it?

Edit : I think this might be more appropriately placed in the "Homework and Coursework" section.
 
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Ruffini's rule speeds up the proces when divisior is in form "x-r"
 
Indeed it does, thanks zoki85!
 
Since the problem is only to find the remainder, even simpler is "The remainder when dividing polynomial function P(x) by x- r is P(r)".
That's easy to prove: let Q(x) be the quotient when P(x) is divided by x- r. The P(x)= Q(x)(x- r)+ remainder. Letting x= r give P(r)= Q(r)(0)+ remainder or "remainder= P(r)". To find the remainder when P(x)= 9x^{23}- 7x^{12}- 2x^5+ 1 is divided by x+1= x- (-1), just calculate
P(-1)= 9(-1)^{23}- 7(-1)^{12}- 2(-1)^5+ 1.
 
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Wow! (high fives HallsofIvy)
 

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