Finding the Value of $n$ in a Rhombus $DBEF$

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SUMMARY

The discussion centers on determining the value of \( n \) in the context of a rhombus \( DBEF \) formed within square \( ABCD \). Given the conditions that \( CF \parallel BD \) and \( DF = DB \), it is established that \( \angle BDF = n \angle F \). The conclusion drawn is that \( n \) must equal 2, as the angles in a rhombus are equal and the geometric properties of the square dictate this relationship.

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Albert1
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$ABCD $ is a square,$CF//BD$, and $DF=DB$,point $E,$ is on $CF$
given :$DBEF$ is a rhombus
if $\angle BDF=n\angle F$(here :$n\in N)$
please find :$n=?$
 
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Albert said:
$ABCD $ is a square,$CF//BD$, and $DF=DB$,point $E,$ is on $CF$
given :$DBEF$ is a rhombus
if $\angle BDF=n\angle F$(here :$n\in N)$
please find :$n=?$
 

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