B Geometry Puzzle with 20 points in a cross pattern

[bob012345]

I do not understand your statement.
There are four squares and every square has four points. Every option must have at least one point from each of these four squares. That means there are $$ \binom{4}{1}\cdot\binom{4}{1}\cdot\binom{4}{1}\cdot\binom{4}{1}=4\cdot4\cdot4\cdot4=256 $$ different options which include one point from each of the four squares. If you exclude mirror and rotation options there will be $256/8=32$ possibilities (the post #20).

If I remember, that was so two weeks ago, probably what I meant by the permutations, was the relative rotations of the squares with missing points which was quicker and easier than checking for mirroring cases first. My 64 drawings include the mirrored cases.

 

[Gavran]

If I remember, that was so two weeks ago, probably what I meant by the permutations, was the relative rotations of the squares with missing points which was quicker and easier than checking for mirroring cases first. My 64 drawings include the mirrored cases.

Okay.