Finding the volume using cylindrical shells

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SUMMARY

The discussion focuses on calculating the volume of a solid of revolution formed by rotating the region bounded by the curve x = 1 + (y - 2)² and the line x = 2 about the x-axis. The correct volume formula is derived using the cylindrical shells method, resulting in the integral 2∏∫(y)(1 + (y - 2)²) dy, with limits of integration from 1 to 3. The final volume calculation yields 16∏/3, correcting the initial miscalculation of 32∏/3 by properly setting up the representative rectangles within the parabola.

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  • Cylindrical shells method for volume calculation
  • Understanding of integration techniques
  • Familiarity with parabolic equations
  • Knowledge of solid of revolution concepts
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  • Explore visualizing solids of revolution using graphing tools
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Students studying calculus, particularly those focusing on volume calculations and solid geometry, as well as educators seeking to clarify the cylindrical shells method.

ThiagoG
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Homework Statement


x=1+(y-2)^2, x=2. Rotating about the x-axis


Homework Equations


Volume=(2∏y)(1+(y-2)2(Δy)

Limits of integration would be from 1 to 3
2∏∫(y)(1+(y-2)2dy
2∏∫y3-4y2+5y dy


The Attempt at a Solution


2∏[y4/4-4y3/3+5y2/2]

Plug in the limits and I get 32∏/3. The answer is 16∏/3. It works if for the circumference you use 2∏ instead of 2∏y.
 
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ThiagoG said:

Homework Statement


x=1+(y-2)^2, x=2. Rotating about the x-axis


Homework Equations


Volume=(2∏y)(1+(y-2)2(Δy)

Limits of integration would be from 1 to 3
2∏∫(y)(1+(y-2)2)dy
Here's where you've gone wrong, I think. The representative rectangles need to be inside the parabola, not outside, as you have set the integral up.
 
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eumyang said:
Here's where you've gone wrong, I think. The representative rectangles need to be inside the parabola, not outside, as you have set the integral up.

How would you fix this?
 
(To help visualize what you did earlier, I attached two pics. The red region is what is being rotated around the x-axis. The "Wrong.bmp" file shows what you did, and the "Right.bmp" file shows what the problem is asking.)

The way you had set it up, your heights of the representative rectangle (or the distance from the y-axis to the parabola) is x (which equals 1 + (y - 2)2). Given that the distance from the y-axis to the line x=2 is 2, can you tell me the height of a rectangle from the parabola to the x=2 line?
 

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eumyang said:
(To help visualize what you did earlier, I attached two pics. The red region is what is being rotated around the x-axis. The "Wrong.bmp" file shows what you did, and the "Right.bmp" file shows what the problem is asking.)

The way you had set it up, your heights of the representative rectangle (or the distance from the y-axis to the parabola) is x (which equals 1 + (y - 2)2). Given that the distance from the y-axis to the line x=2 is 2, can you tell me the height of a rectangle from the parabola to the x=2 line?

So it would be 3+(y-2)2?

edit: I tried this and it didn't work
 
No, you don't want to add 2 and 1 + (y - 2)2.
 
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eumyang said:
No, you don't want to add 2 and 1 + (y - 2)2.

I subtracted 2 from it. So my integral is 2∏∫(y)(-1+(y-1)2)dy. I got a negative number when I did this.
 
Almost. Switch the order of subtraction.
 
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eumyang said:
Almost. Switch the order of subtraction.

Ok thank you so much for your help. :)
 

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