Finding the x-intercept

  • Thread starter MrNeWBiE
  • Start date
  • #1
MrNeWBiE
75
0

Homework Statement



Find the x-intercept of the line that passes through the point (1; 2) and perpendicular to the
line joining (1; 1) and (3; 4):



The Attempt at a Solution



I want to confirm my steps if it's right ,,,,

M=(4-1)/(3-1)= 3/2

y-1=3/2(x-1) ====> y=(3/2)x-1/2

perpendicular = m1xm2=-1 ====> m2=-2/3

y-2=-2/3(x-1) ====> y=(-2/3)x+4/5


making it one equation

(3/2)x-(1/2)=(2/3)x+(4/3)
x=11/13
 

Answers and Replies

  • #2
benhou
123
1
making it one equation

(3/2)x-(1/2)=(2/3)x+(4/3)
x=11/13

I am not sure what you did here. I am assuming you were trying to combine the equation of the first line with the second line. If so, you have calculated the point of intersection of the two lines, which is not what the question has asked for. The question asked you for the x-intercept of the line.
 
  • #3
MrNeWBiE
75
0
aha ,,,
so I should not combine them ,,,

(-2/3)x+4/5 = 0 ?

and the answer will be (10/13,0)
 
  • #4
benhou
123
1
Looks good to me!
 
  • #5
MrNeWBiE
75
0
ops ,,,
I had a mistake in y=(-2/3)x+4/5 ,,, should be y=(-2/3)x+8/3

the answer is (4,0) ,,,

btw the for your helping
 

Suggested for: Finding the x-intercept

Replies
4
Views
319
Replies
4
Views
272
Replies
8
Views
1K
Replies
16
Views
552
  • Last Post
Replies
7
Views
563
  • Last Post
Replies
4
Views
519
Replies
3
Views
347
  • Last Post
Replies
17
Views
268
Replies
7
Views
315
Top