Finding Time from Accel and Distance

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SUMMARY

This discussion focuses on calculating the time required to travel 0.05 miles at a given acceleration, starting from an initial speed. The user has determined an average acceleration of 8.57 mph/s for a car that accelerates from 0 to 60 mph in 7 seconds. Using the kinematic equation (V_f)^2 = (V_i)^2 + 2a(d_f), the user can derive both the time taken and the final speed after traveling the specified distance. The discussion emphasizes the importance of constant acceleration in these calculations.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of acceleration and speed
  • Familiarity with units of measurement (miles, mph)
  • Ability to perform algebraic manipulations
NEXT STEPS
  • Research the application of kinematic equations in real-world scenarios
  • Learn how to calculate average acceleration from speed and time
  • Explore the implications of constant versus variable acceleration
  • Investigate simulation tools for modeling vehicle dynamics
USEFUL FOR

Game developers, automotive engineers, physics students, and anyone interested in vehicle performance calculations will benefit from this discussion.

BlueBob88
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Not school related, but I guess it could be a homework problem.
I am redoing my racing script on my car game and need some help. I have been looking around in many places and can't seem to find how to do this problem.

Homework Statement


I need to find the time it takes to travel 0.05 miles at a given acceleration starting at a given speed. I also need to find out the final speed.

So if a car starts from a stop (0 mph) and can travel 0-60mph in 7 seconds. How long will it take to travel 0.05 miles and what will its final speed be.

Homework Equations


time = change/acceleration
d=st

The Attempt at a Solution


So far I have its average acceleration at 8.57 mph/s if I can find the time I will be able to find its final speed. If its 1 second it will be 8.75 mph, 2 seconds will be 35mph. (Not to sure on that) But I did (2 seconds^2) * 8.75
 
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Is it going to be a constant acceleration? If it is you can use

[tex](V_f)^2=(V_i)^2+2a(d_f)[/tex]

Where [tex]V_f =[/tex] Final Velocity, [tex]V_i =[/tex] Initial Velocity, [tex]d_f =[/tex] the final displacement.

From there you can find the time it takes in a multitude of ways.
 
Last edited:

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