Finding time given acceleration and velocity

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To determine when Particle A passes Particle B, the relevant kinematic equations for constant acceleration must be applied. Particle A has an initial velocity of 14.3 m/s and an acceleration of 4.15 m/s², while Particle B starts with a head start of 46 m, an initial velocity of 7.85 m/s, and an acceleration of 2.68 m/s². The discussion emphasizes identifying the correct formula that incorporates these variables to solve for the time at which A overtakes B. Participants suggest using equations that relate displacement, velocity, and acceleration to find the solution. Proper application of these kinematic equations will yield the time in seconds when Particle A passes Particle B.
stacerho
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I am having troubles with a physics question. I can't figure out what formula to use to solve the following question:

Particle A passes a point with an initial velocity of 14.3 m/s and an acceleration of 4.15 m/x^2. Particle B has a 46 m head start at 7.85 m/s with an acceleration of 2.68 m/s^2. At what time will A pass B? Answer in units of s.

Any suggestions.
 
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Have you come across the kinematic equations for constant acceleration? Which one of these do you think you should use, considering the variables you are given?
 
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