Finding time when rocket engine fails at 1055 m/s

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 1K views
Jregan
Messages
3
Reaction score
1
Homework Statement
A rocket accelerates vertically with a constant acceleration of 21.1m/s/s until it’s engine fails after 50 seconds. The rocket reaches an altitude of 26375m when the engine fails. When does the rocket reach its max height? (Ignoring air resistance)
I don’t understand how the equations given in the hint work with this question.
Relevant Equations
The hint says vi=a*delta t and vf=vi-g*delta t
21.1*50=1055
1055m/s is the velocity when the engine fails.
I don’t know what the time should be in the second equation.
 
Physics news on Phys.org
Jregan said:
21.1*50=1055
1055m/s is the velocity when the engine fails.
Good. Take the instant that the engine fails to be the beginning of the second phase of the motion.
 
  • Like
Likes   Reactions: Jregan