Finding Time when throwing an object up

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Homework Help Overview

The problem involves calculating the time it takes for a ball thrown straight up from a height of 55 meters to hit the ground, with an initial speed of 35 m/s. The subject area pertains to kinematics in physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of different kinematic equations, with one suggesting the equation d = vot + 1/2at². Others explore the idea of calculating the maximum height reached by the ball and how that relates to the total time of flight.

Discussion Status

The discussion is ongoing, with participants offering various approaches and equations to consider. There is no explicit consensus yet, but multiple interpretations of the problem are being explored.

Contextual Notes

Some participants question the appropriateness of the initial equations used and whether additional information about the maximum height is necessary for solving the problem.

SunKissedGal1
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Homework Statement



Standing on the top ledge of a 55 meter high building you throw a ball straight up with an initial speed of 35 m/s. How long, to the nearest second, does it take to hit the ground?

Homework Equations



v= at + vo

The Attempt at a Solution



i think I am using the wrong equation...
X= 55
V= 35
a=9.8
t=?
 
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Try using: d=vot +1/2at2
 
Maybe if you figured how high it would go you could figure how long it will take to hit the ground from that total height? And then that added to how long it took to get to that height would be your total time wouldn't it?
 
LowlyPion said:
Maybe if you figured how high it would go you could figure how long it will take to hit the ground from that total height? And then that added to how long it took to get to that height would be your total time wouldn't it?

Right, you would need, 2ad = vf2-vi2
 

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