A projectile is shot upward from the top of a cliff in an angle of 25 with a velocity of 195 m/s.The height of the cliff is 315m. What will be its speed when it strikes the ground below? (Use conservation of energy)
Ok...initial energy = final energy
Initial energy = .5m*(initial velocity square) + mgy
Final energy = .5m*(final velocity square)
initial velocity = sin*theta*upward initial velocity = sin25*195
The Attempt at a Solution
So I set them to equal and I got final V to be 114, but it says I had it wrong, canceling out the mass.... I have no clue what I did wrong there...