Finding volume ratio in thermodynamic cycle using PV^y = constant

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
9 replies · 2K views
subzero0137
Messages
91
Reaction score
4
therm.png
2. PV^y = const, y=Cp/Cv, PV=nRT, 3.
thermaaa.png


I've drawn the cycle for part a) of the question, but I'm not sure how to do part b). I know I need to relate Vm and 4Vo using the PV^y = constant relation but I'm stuck as to how to do it.
 
Physics news on Phys.org
subzero0137 said:
I know I need to relate Vm and 4Vo using the PV^y = constant relation
Using that, write an equation relating P0, V0, Pm and Vm.
 
  • Like
Likes   Reactions: subzero0137 and Chestermiller
haruspex said:
Using that, write an equation relating P0, V0, Pm and Vm.

Thanks, I think I got it now. Just to confirm, would P_m = P_0/32?
 
subzero0137 said:
Thanks, I think I got it now. Just to confirm, would P_m = P_0/32?
Yes.
 
haruspex said:
Yes.

Sorry to bother you again but the next part of the questions asks to determine the work done, heat transfer and change in internal energy in each process. So if we consider the first, isobaric process then the work done on the gas is simply Won = -P0 * (4V0 - V0) = -P0 * 3V0. To calculate the heat transferred (Q) and change in internal energy (ΔU) I can use the first law of thermodynamics, but the equations for Q and ΔU involve variables that I don't know. ΔU=nCVΔT and Q=nCPΔT. I don't know how to get either Q or ΔU if I don't know n (moles) and change in temperature.
 
subzero0137 said:
Sorry to bother you again but the next part of the questions asks to determine the work done, heat transfer and change in internal energy in each process. So if we consider the first, isobaric process then the work done on the gas is simply Won = -P0 * (4V0 - V0) = -P0 * 3V0. To calculate the heat transferred (Q) and change in internal energy (ΔU) I can use the first law of thermodynamics, but the equations for Q and ΔU involve variables that I don't know. ΔU=nCVΔT and Q=nCPΔT. I don't know how to get either Q or ΔU if I don't know n (moles) and change in temperature.
Try it algebraically, also making use of the ideal gas law, and see how it plays out. I think you will be pleasantly surprised.
 
Last edited:
Chestermiller said:
Do it "per mole."

ΔU=CVΔT and Q=CPΔT? But the temperature differences are still missing. I tried to do P0V0/T1 = P04V0/T2 ⇒ T2=4T1 but that doesn't give a change in temperature
 
$$nT_0=\frac{P_0V_0}{R}$$
$$nT_1=\frac{P_0(4V_0)}{R}$$
$$nC_v(T_1-T_0)=C_v\frac{3P_0V_0}{R}$$
For a monoatomic gas, what is the molar Cv in terms of R?
 
Chestermiller said:
$$nT_0=\frac{P_0V_0}{R}$$
$$nT_1=\frac{P_0(4V_0)}{R}$$
$$nC_v(T_1-T_0)=C_v\frac{3P_0V_0}{R}$$
For a monoatomic gas, what is the molar Cv in terms of R?

Molar Cv = 3/2 R? Sorry I'm still confused
 
Last edited:
subzero0137 said:
Molar Cv = 3/2 R? Sorry I'm still confused
$$\Delta U=nC_v\Delta T=\left(\frac{3R}{2}\right)\frac{3P_0V_0}{R}=?$$
 
  • Like
Likes   Reactions: subzero0137