Finding X and Y components of a vector of magnitude

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To find the x and y components of a vector, use the formulas Vx = R * Cos(θ) and Vy = R * Sin(θ), where R is the vector's magnitude and θ is its direction. For a vector of magnitude 25 m/s at 45 degrees, the components can be calculated as Vx = 25 * Cos(45) and Vy = 25 * Sin(45). Similarly, for a vector of 75 N at 60 degrees, use Vx = 75 * Cos(60) and Vy = 75 * Sin(60). Visualizing the vector on a coordinate system helps clarify the relationship between the hypotenuse and its components, forming a right triangle. Understanding these geometric principles is essential for accurately determining vector components.
Sonny18n
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1. A- What are the x and y components of a vector of magnitude 25m/s and direction of 45 degrees?

B- What are the x and y components of a vector of magnitude 75N and a direction of 60 degrees.2. Are these the formulas you use?

Vx=(R)Cos0
Vy=(R)Sin0
3. help please
 
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Welcome to PF;
Never mind trying to figure out which formula is for which - instead, use your knowledge of geometry.
Start by drawing out a pair of x and y axes, then sketch the vector on those axes.
If you draw a dotted line at 90deg from the x-axis to the tip of the vector arrow, you will have a triangle where the vector is the hypotenuse.
The components are the other two sides.
 
90 degrees? As in a right angle? Can you clarify that
 
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90 degrees? As in a right angle? Can you clarify that
That's right - "deg" = "degrees" (it's easier to type than those little circles).
90deg = (pi/2)rad = "perpendicular to" = (yes) the right angle.
It's how you normally read off a coordinate from an axis.

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