MHB Finding X & Y Components of Vectors

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SUMMARY

The discussion focuses on calculating the x and y components of a vector using trigonometric functions. The formulas used are Ax = A cos(θ) for the x component and Ay = A sin(θ) for the y component. For a vector of 9.55m at an angle of -48.0 degrees, the correct calculation for Ay results in approximately -7.10m, confirming the importance of ensuring the calculator is set to the correct mode and applying the property of sine for negative angles.

PREREQUISITES
  • Understanding of basic trigonometric functions (sine and cosine)
  • Familiarity with vector components in physics
  • Ability to convert angles between degrees and radians
  • Knowledge of calculator settings for trigonometric calculations
NEXT STEPS
  • Study the unit circle and its application in trigonometry
  • Learn about vector addition and subtraction in physics
  • Explore the concept of angle measurement in both degrees and radians
  • Practice solving vector problems using different angles and magnitudes
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Students learning physics, particularly those focusing on vector analysis, as well as educators teaching trigonometry and its applications in real-world scenarios.

Coder74
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Im learning about how to find the x and y components of a vector, but I wanted to verify if I'm on the right track..

Ax=A cos(\theta) <-- solving for x

Ay=A sin(\theta) <-- solving for y

So if a vector is 9.55m long and points in a -48.0 degree direction.

Is it Ay= 9.55 sin(-48.0)=7.3
 
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I get:

$$A_y=9.55\sin\left(-48^{\circ}\right)\text{ m}=-9.55\sin\left(48^{\circ}\right)\text{ m}\approx-7.10\text{ m}$$

Your calculator is in radian mode...and don't forget $\sin(-x)=-\sin(x)$...:D
 

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