Finding Y-Bar for a Constant Density Region

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SUMMARY

The discussion focuses on calculating the centroid Y-bar for a region with constant density bounded by the curves y=x-x^2 and y=-x. The formula used for Y-bar is derived from the instructor's guidelines, involving integrals of the squared functions and their differences. The calculations initially yield Y-bar = 2/5, but the correct answer is identified as -3/5. This highlights the importance of careful integration and verification in solving such problems.

PREREQUISITES
  • Understanding of integral calculus, specifically definite integrals.
  • Familiarity with the concept of centroids in physics and geometry.
  • Knowledge of the properties of functions and their intersections.
  • Experience with applying density concepts in physical problems.
NEXT STEPS
  • Review the derivation of centroids for various shapes using integral calculus.
  • Practice solving problems involving bounded regions and constant density.
  • Explore the application of the centroid formula in real-world physics problems.
  • Learn about the implications of negative values in centroid calculations.
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Students studying calculus, particularly those focusing on applications in physics and engineering, as well as educators looking for examples of centroid calculations in bounded regions.

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Homework Statement


constant density. region bounded by y=x-x^2, y=-x.


Homework Equations


this is according to the formula my instructor gave me:

Y(bar) - (1/2)(integral)(a to b)(δ)(f(x) ^2 - g(x)^2) dx
-----------------------------------------------
(integral)(a to b) (δ) (f(x) - g(x)) dx

The Attempt at a Solution



Y(bar) = (1/2) (integral)(0 to 2) [ δ ((x-x^2)^2 - (-x)^2) dx ]
----------------------------------------------------
(integral)(0 to 2) [δ ((x-x^2) - (-x)) dx]

(1/2)(integral) (0 to 2) [δ (-2x^2 + x^4) dx ] = 8δ/15
(integral)(0 to 2) [δ ((x-x^2) - (-x)) dx] = 4δ/3

Y(bar) = 2/5 ; however, the answer is -3/5.
 
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sorry. solved.
 

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