Finding zeros and multiplicity of (x+4)(x-2)³(x²+2x-8)

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(x+4) (x-2)^3 (x^2+2x-8)

would it be -4 multiplicity of 2
and 2 multiplicity of 4?
 
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Yes, that's correct since the quadratic factor is the product of the other two linear factors.
 
in other words,
[tex](x+ 4)(x- 2)^3(x^2- 2x- 8)= (x+ 4)(x- 2)^3(x- 2)(x+ 4)= (x+ 4)^2(x- 2)^4[/tex]
as I am sure you realized.
 

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