Undergrad Finite difference method for Schrödinger equation

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SUMMARY

The discussion focuses on solving the time-independent Schrödinger equation using the finite difference method. The equation is discretized on a lattice of N points, and the second-order derivative is approximated using the central difference formula. The validity of this approximation is established through the dispersion relation derived from the tight-binding model, indicating that the approximation holds when the lattice spacing (Δx) is significantly smaller than the wavelength (1/k). The connection between the energy expression and the operator form of the second derivative is clarified through the relationship between momentum and wave number.

PREREQUISITES
  • Understanding of the Schrödinger equation and quantum mechanics
  • Familiarity with finite difference methods for numerical analysis
  • Knowledge of Taylor series expansion and its application in approximations
  • Basic concepts of wave functions and operators in quantum mechanics
NEXT STEPS
  • Study the finite difference method for solving partial differential equations
  • Explore the tight-binding model in quantum mechanics
  • Learn about the dispersion relations in quantum systems
  • Investigate the relationship between wave functions and momentum operators
USEFUL FOR

Quantum physicists, computational physicists, and students studying numerical methods in quantum mechanics will benefit from this discussion.

aaaa202
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Suppose I want to solve the time-independent Schrödinger equation
2/2m ∂2/∂x2 + V)ψ = Eψ
using a numerical approach. I then discretize the equation on a lattice of N points such that x=(x1,x2,...,xN) etc. Finally I approximate the second order derivative with the well known central difference formula:
2/∂x2 ≈ 1/Δx2i+1i-1-2ψi)
My question is now: How do you estimate the validity of this approximation? I have already talked to my teacher about it and he said the following:
The discrete approximation is a tight-binding model with dispersion:
E = ħ2/2m * 2/Δx2(1-cos(kΔx))
So for Δx<<1/k we can taylor expand this expression to give:
E ≈ ħ2/2m * 2/Δx2(1-(1-1/2(kΔx)2))=ħ2k2/2m
Which, according to my teacher, shows that the approximation holds provided that the lattice spacing is much shorter than the wavelength. What I don't get is how you can argue that because the dispersion is parabolic in k the finite difference approximation for the derivative ∂2/∂x2 is a good approximation. In short: What "connects" ħ2k2/2m with ħ2/2m ∂2/∂x2?
 
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aaaa202 said:
In short: What "connects" ħ2k2/2m with ħ2/2m ∂2/∂x2?
You mean apart from the fact that ##p = \hbar k## and ##\hat{p}^2= -\hbar^2 \frac{d^2}{dx^2}##?
 
But k is not an operator in this case. It is a wavenumber. What connects the number form with the operator form?
 
aaaa202 said:
But k is not an operator in this case. It is a wavenumber. What connects the number form with the operator form?
Plane waves. Eigenfunctions of the ##\hat{p}^2## operator are of the form ##\exp(i k x)## where ##k = p/\hbar##, with ##p## the momentum of the corresponding plane wave.
 

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