Finite Hilbert Space v.s Infinite Hilbert Space in Perturbation Theory

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Discussion Overview

The discussion revolves around the concept of a complete set of states in the context of perturbation theory, specifically comparing finite and infinite Hilbert spaces. Participants explore whether the eigenstates of the unperturbed Hamiltonian remain a complete set when a perturbed Hamiltonian is introduced.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants suggest that the complete set of states can still be used as a basis in Hilbert space when perturbations are applied, likening it to rotating a vector in a geometric vector space.
  • Others caution that issues may arise if the unperturbed and perturbed Hamiltonians exist in Hilbert spaces of different dimensionalities, such as when one has a discrete spectrum and the other has a continuous spectrum.
  • A participant references Haag's theorem in quantum field theory, indicating that the eigenstates of the free Hamiltonian do not generally span the Hilbert space of the full interacting theory.
  • Concerns are raised about the interaction potentially necessitating a change in the Hilbert space, although examples of this in perturbation theory are not readily available.
  • One participant provides a specific example involving the infinite square well and a perturbation that alters the potential, leading to a change in the associated Hilbert space and the failure of original solutions to span the new space.
  • Another participant notes that the operators involved may not be defined on the total Hilbert space but only on dense subsets, which could complicate the application of perturbation theory.

Areas of Agreement / Disagreement

Participants express differing views on whether the complete set of states remains valid under perturbation, with some asserting it does and others highlighting potential complications. The discussion does not reach a consensus on these points.

Contextual Notes

Participants mention limitations related to the definitions of operators and the conditions under which perturbation theory can be applied, particularly regarding the boundedness of the perturbation relative to the unperturbed Hamiltonian.

ck00
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Hi all,
I have a question about the concept of complete set when I apply the perturbation theory in two situations -Finite Hilbert Space and Infinite Hilbert Space.
Consider a Hamiltonian H=H0+H', where H0 is the unperturbed Hamiltonian and H' is the perturbed Hamiltonian. Let ψ_n be the complete set of unperturbed Hamiltonian H0.

Do ψ_n still constitute a complete set of the overall Hamiltonian H for either finite Hilbert space or infinite Hilbert space if the perturbed Hamiltonian is turned on?

Ck
 
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ck00 said:
Hi all,
I have a question about the concept of complete set when I apply the perturbation theory in two situations -Finite Hilbert Space and Infinite Hilbert Space.
Consider a Hamiltonian H=H0+H', where H0 is the unperturbed Hamiltonian and H' is the perturbed Hamiltonian. Let ψ_n be the complete set of unperturbed Hamiltonian H0.

Do ψ_n still constitute a complete set of the overall Hamiltonian H for either finite Hilbert space or infinite Hilbert space if the perturbed Hamiltonian is turned on?

Ck

You can think of a complete set of states as a basis in Hilbert space, much like an ordinary (geometrical) vector space. A state of the Hamiltonian H0 can be seen as a vector in this Hilbert space, which may be one of the basis states, or a linear combination of several of them. So if you change your state by perturbing it, you are basically just rotating your vector into a new one, which can still be described using the same basis. This works both for finite and infinite dimensional Hilbert spaces. (Strictly speaking, infinite dimensional spaces require some additional care mathematically, but for physics intuition one can use the same picture.)

I assume you could run into some problems if H0 and H' live in Hilbert spaces of different dimensionality though (eg. H0 has a discrete spectrum, while H' has a continuous one), but I don't think I've ever seen that happen in practice. I'm speculating now, but to me it seems you should be able to use an overcomplete set of states then.
 
ck00 said:
Do ψ_n still constitute a complete set of the overall Hamiltonian H for either finite Hilbert space or infinite Hilbert space if the perturbed Hamiltonian is turned on?
In the case of QFT, you could look up "Haag's theorem" which implies that, in general, the eigenstates of the free Hamiltonian fail to span the Hilbert space of the full interacting theory.
 
The only problem I am aware of is when the interaction forces us to change the Hilbert space. But I am not aware of any reasonable example in perturbation theory.
 
Hypersphere said:
You can think of a complete set of states as a basis in Hilbert space, much like an ordinary (geometrical) vector space. A state of the Hamiltonian H0 can be seen as a vector in this Hilbert space, which may be one of the basis states, or a linear combination of several of them. So if you change your state by perturbing it, you are basically just rotating your vector into a new one, which can still be described using the same basis. This works both for finite and infinite dimensional Hilbert spaces. (Strictly speaking, infinite dimensional spaces require some additional care mathematically, but for physics intuition one can use the same picture.)

I assume you could run into some problems if H0 and H' live in Hilbert spaces of different dimensionality though (eg. H0 has a discrete spectrum, while H' has a continuous one), but I don't think I've ever seen that happen in practice. I'm speculating now, but to me it seems you should be able to use an overcomplete set of states then.

Thank you for your answering. I have a follow-up question.
Consider 2x2 Hamiltonian H=H0+H'.
Let Φ_a and Φ_b be two eigenstates of H0 and ψ_a and ψ_b be two eigenstates of H.
What is the relation between {Φ_a, Φ_b} and {ψ_a, ψ_b}? Are they just linear combination of each other?
 
tom.stoer said:
The only problem I am aware of is when the interaction forces us to change the Hilbert space. But I am not aware of any reasonable example in perturbation theory.

What is the meaning of change of Hilbert space?
 
Consider the infinite square well with
V(x) = 0 for a<x<b (I)
V(x) = +∞ for x<a or x>b (II)
The associated Hilbert space is L²[a,b]; the region (II) is excluded.

Now consider a (large!) perturbation which changes the potential to
V(x) = 0 for a<x<b (I)
V(x) = V0 for x<a or x>b (II)
The associated Hilbert space is now L²[-∞,+∞]; the region (II) can no longer be excluded; the solutions for the original case do not span this new Hilbert space. Of course this change of the Hilbert space must not and cannot be treated perturbatively.

This may seem to be rather artificial, but there are physically relevant problems were similar problems occure. Consider an atom with an 1/r potential. It has well-known bound states plus a continuum of scattering states. Now add a constant electric field which results from a linear potential U(x) = u0x. The resulting Hamiltonian is no longer bounded from below; at first glance the problem is not even well-defined mathematically.
 
ck00 said:
Hi all,
I have a question about the concept of complete set when I apply the perturbation theory in two situations -Finite Hilbert Space and Infinite Hilbert Space.
Consider a Hamiltonian H=H0+H', where H0 is the unperturbed Hamiltonian and H' is the perturbed Hamiltonian. Let ψ_n be the complete set of unperturbed Hamiltonian H0.

Do ψ_n still constitute a complete set of the overall Hamiltonian H for either finite Hilbert space or infinite Hilbert space if the perturbed Hamiltonian is turned on?

Ck

The problem is usually that H and H0 are unbound operators and are not defined on the total Hilbert space but only on dense subsets. These ranges of definition do not coincide in general, e.g. when H' is a delta function. They do coincide iff H' is relatively bounded wrt H0 with bound <1 (Kato-Rellich theorem).
I found references where these terms are explained here
http://www.math.pku.edu.cn/teachers/fanhj/courses/fl5.pdf
or here
http://www.fuw.edu.pl/~derezins/mat-u.pdfThe reference of the expert on perturbation theory is
Tosio Kato,
Perturbation Theory for Linear Operators
 
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