Finite Metric Space Imbedding in Manifolds

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SUMMARY

Every finite metric space can potentially be embedded in a manifold, specifically in connected and Riemannian manifolds. The discussion highlights the challenge of embedding finite metric spaces with varying numbers of points, suggesting a systematic approach starting from 0 to 4 points. The example provided illustrates a finite metric space with 4 points that may not be embeddable, although a definitive proof is lacking. This indicates the complexity of the problem and the need for further exploration in the field of metric geometry.

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  • Understanding of finite metric spaces and their properties
  • Familiarity with Riemannian manifolds and their characteristics
  • Knowledge of geodesics and their role in metric spaces
  • Basic concepts of topology related to connectedness
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Dragonfall
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Is every finite metric space imbeddable in a manifold?

That is, for every finite metric space (X,d), does there exist some manifold such that there are |X| many points on it which is isometric (with the length of geodesics as metric) to (X,d)?
 
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Can you do a set with 4 points?
 
What do you mean?
 
"Every finite metric space" is a tall order. Try starting with embedding "every metric space with 4 points" into Riemannian manifolds. (Actually, why not start with 0, 1, 2, 3, and then 4?)

(P.S. I assume you mean "connected and Riemannian" manifolds?)
 
OK, it seems this one

o
\
o ---- o
/
o

where the metric is the number of steps between nodes, can't be done. But I can't prove it conclusively.
 

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