LagrangeEuler
- 711
- 22
I am not sure how is it possible that asymetric potential well does not have bond states if ##E<U_1<U_2##. In symmetric case solution always exists. Why this is a case?
The discussion centers on the existence of bound states in asymmetric finite square wells compared to symmetric ones. It is established that while symmetric potential wells always possess bound state solutions, asymmetric wells do not guarantee this outcome. The participants highlight that for asymmetric potential wells, an explicit equation can be derived to determine the energies of bound states, confirming that at least one bound state exists under certain conditions.
PREREQUISITESStudents and professionals in quantum mechanics, physicists analyzing potential wells, and educators teaching advanced quantum theory concepts.
I may be misunderstanding the question here... The asymmetric finite square well does have bound state solutions.LagrangeEuler said:I am not sure how is it possible that asymetric potential well does not have bond states if ##E<U_1<U_2##. In symmetric case solution always exists. Why this is a case?