# Finite well penetration depths dependence on Well Length

1. Mar 30, 2014

### PsychonautQQ

So in the infinite well Energy is proportional to 1/L^2, so i'm assuming in the finite well there is some sort of similar relation. So as the L decreases, the energy increases, so the wavelength decreases. Decreasing the wavelength means more energy, so it should penetrate further, but also if you draw the situation a smaller wavelength will make it penetrate less far, although the well also is getting smaller so blahh i'm trying to figure out how all this adds up. Thanks!

2. Mar 30, 2014

### The_Duck

What do you mean by this? I don't think it's correct.

I suggest you actually work through the solution of the finite square well and see how the penetration length of the ground state wave function depends on L.

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