First harmonic question ( from Aqa paper)

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SUMMARY

The discussion centers on the calculation of the fundamental frequency (F) of a vibrating wire, specifically addressing the formula F = (1/2l) * √(Tension/mass per unit length). The user initially assumes that when the length of the wire is doubled, the mass per unit length changes, leading to confusion regarding the final answer of F/√2. The conclusion drawn is that doubling the length of the wire does affect the mass, which is crucial for understanding the frequency calculation.

PREREQUISITES
  • Understanding of wave mechanics and harmonic frequencies
  • Familiarity with the concepts of tension and mass per unit length in strings
  • Knowledge of the mathematical manipulation of square roots and fractions
  • Basic principles of physics related to vibrating systems
NEXT STEPS
  • Research the effects of changing wire length on frequency in vibrating strings
  • Explore the derivation of the wave equation for strings under tension
  • Learn about the relationship between tension, mass, and frequency in string instruments
  • Investigate harmonic series and their applications in musical acoustics
USEFUL FOR

Physics students, educators, and anyone interested in the principles of wave mechanics and harmonic frequencies in vibrating systems.

bonbon22
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Homework Statement
https://filestore.aqa.org.uk/sample-papers-and-mark-schemes/2016/june/AQA-74072-QP-JUN16.PDF

it is the multiple choice question number 13
Relevant Equations
first harmonic equation
The answer is f/square root 2

If F = 1/2l * square root ( Tension/ mass per unit length )
---------> this becomes I am assuming 1/2l * square root ( length * Tension/ mass )
this would give an answer of F

yet the answer is F/ square root (2)
 
Physics news on Phys.org
Does anything happen to the mass ##m## when the length of the wire is doubled?
 
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Likes   Reactions: bonbon22
TSny said:
Does anything happen to the mass ##m## when the length of the wire is doubled?
ahhh i see ... cheers
 

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