First order nonlinear ODE - Integrating factor + exact differentials, or not?

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The discussion revolves around solving a first-order nonlinear ordinary differential equation (ODE) given by dy/dx = (x^2 - y^2)/(x^2 + 5yx). The original poster attempts to find an integrating factor or convert the equation into an exact differential but finds that it does not satisfy the conditions for exactness. They also explore the possibility of an integrating factor that is a function of both variables but struggle to identify suitable constants. A suggested approach involves using the substitution v = y/x, which simplifies the equation into a separable form, allowing for a solution to be derived. This method provides a pathway to solving the nonlinear ODE effectively.
LawlQuals
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First order nonlinear ODE -- Integrating factor + exact differentials, or not?

Hello everyone,

(I apologize if this did not format properly, if not I will attempt to edit it if that functionality is available upon submitting a question).

I recently came across the following nonlinear ODE that I am having difficulty in solving.

Homework Statement



Determine the general solution to the differential equation:

\frac{dy}{dx} = \frac{x^2 - y^2}{x^2 + 5yx} = \frac{(x+y)(x-y)}{x(x + 5y)}

Homework Equations



Any methods up to and including a typical advanced engineering mathematics (undergrad) course (integrating factors, variation of parameters, transforms, exact differentials, etc.)

The Attempt at a Solution



My only ideas have involved forcing the equation to be an exact differential. However, I have not been able to come to a solution by this route. To demonstrate, I pursued putting the equation in the form of conventional notation for exact differentials,

<br /> \underbrace{(x^2 - y^2)}_{=\, M}dx - \underbrace{(x^2 + 5yx)}_{=\, -N}dy = 0 <br />

<br /> Mdx + Ndy = 0<br />

where

M = x^2 - y^2 \Rightarrow M_x = 2x, \quad M_y = -2y
N = -(x^2 + 5yx) \Rightarrow N_x = -2x - 5x \quad N_y = 5x

and the subscripts denote differentiation with respect to the labeled parameter. It is evident it is not exact (M_y \neq N_x). Further, I was unable to implement an integrating factor \sigma such that \frac{\partial}{\partial y}(\sigma M) = \frac{\partial}{\partial x} (\sigma N) upon multiplication of the entire equation by \sigma. It can readily be seen that the integrating factor \sigma is not only a function of x or y, e.g. writing out the condition for exact differentials involving the factor \sigma, and enforcing \sigma to be a function of x or y alone involves results of the form

\frac{\sigma_y}{\sigma} \sim \frac{M_y - N_x}{M}

or

\frac{\sigma_x}{\sigma} \sim \frac{M_y - N_x}{N}

which demonstrates that \sigma is a function of both variables in either case (in contradiction to the posits that lead to these equations).

Choosing a form \sigma (x,y) = x^a y^b, I could not discern proper constants a, and b.

Does anyone have any suggestions regarding solving this equation? Thanks very much for any insight, and take care.
 
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LawlQuals said:
Hello everyone,

(I apologize if this did not format properly, if not I will attempt to edit it if that functionality is available upon submitting a question).
No need for apologies - what you have looks great.
LawlQuals said:
I recently came across the following nonlinear ODE that I am having difficulty in solving.

Homework Statement



Determine the general solution to the differential equation:

\frac{dy}{dx} = \frac{x^2 - y^2}{x^2 + 5yx} = \frac{(x+y)(x-y)}{x(x + 5y)}

Homework Equations



Any methods up to and including a typical advanced engineering mathematics (undergrad) course (integrating factors, variation of parameters, transforms, exact differentials, etc.)

The Attempt at a Solution



My only ideas have involved forcing the equation to be an exact differential. However, I have not been able to come to a solution by this route. To demonstrate, I pursued putting the equation in the form of conventional notation for exact differentials,

<br /> \underbrace{(x^2 - y^2)}_{=\, M}dx - \underbrace{(x^2 + 5yx)}_{=\, -N}dy = 0 <br />

<br /> Mdx + Ndy = 0<br />

where

M = x^2 - y^2 \Rightarrow M_x = 2x, \quad M_y = -2y
N = -(x^2 + 5yx) \Rightarrow N_x = -2x - 5x \quad N_y = 5x

and the subscripts denote differentiation with respect to the labeled parameter. It is evident it is not exact (M_y \neq N_x). Further, I was unable to implement an integrating factor \sigma such that \frac{\partial}{\partial y}(\sigma M) = \frac{\partial}{\partial x} (\sigma N) upon multiplication of the entire equation by \sigma. It can readily be seen that the integrating factor \sigma is not only a function of x or y, e.g. writing out the condition for exact differentials involving the factor \sigma, and enforcing \sigma to be a function of x or y alone involves results of the form

\frac{\sigma_y}{\sigma} \sim \frac{M_y - N_x}{M}

or

\frac{\sigma_x}{\sigma} \sim \frac{M_y - N_x}{N}

which demonstrates that \sigma is a function of both variables in either case (in contradiction to the posits that lead to these equations).

Choosing a form \sigma (x,y) = x^a y^b, I could not discern proper constants a, and b.

Does anyone have any suggestions regarding solving this equation? Thanks very much for any insight, and take care.
Try this substitution: Let v = y/x ==> y = vx ==> y' = v'x + v

Then the DE y' = (x^2 - y^2)/(x^2 + 5xy) becomes
v'x + v = (x^2 - v^2 x)/(x^2 + 5vx^2)
v&#039;x + v = \frac{x^2 - v^2x^2}{x^2 + 5vx^2}

After a bit of algebraic manipulation, you get a DE in v and x that is separable. Undo the substitution and you have your solution.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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