An inexact differential equation

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SUMMARY

The discussion focuses on solving an inexact differential equation defined by M = sin(y)cos(y) + xcos²(y) and N = x. The user attempts to apply the theorems for integrating factors (I.F.) but finds that neither theorem holds true for their equation. They explore alternative approaches, including rewriting N and using the derivative of tangent, but do not achieve a solution.

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  • Understanding of differential equations, specifically inexact differential equations.
  • Familiarity with integrating factors and their application in solving differential equations.
  • Knowledge of trigonometric identities and derivatives, particularly involving sine, cosine, and tangent functions.
  • Proficiency in substitution methods for solving differential equations.
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Mathematics students, educators, and professionals dealing with differential equations, particularly those focusing on inexact forms and seeking to enhance their problem-solving techniques.

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Homework Statement
Solve the following differential equation:
(siny*cosy +xcos^2(y))dx + xdy=0
Relevant Equations
##\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x} ##
So equation is inexact.
Here, M = ##siny*cosy +xcos^{2}y ## and N = x
## M_y = (1/2)cos(2y) -xsin(2y)##
and ##N_x = 1##

Theorems:
If R = ## \frac{1}{N} (M_y - N_x) = f(x), then I.F. = e^{ \int f(x) dx} ##
If R = ## \frac{1}{M} (N_x - M_y) = g(y), then I.F. = e^{ \int g(x) dx} ##

Neither is holding true.
What should I do?

I tried writing N = ## x(sin^{2}y + cos^{2}y)## thinking it may help, but it didn't.
 
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Try to divide by ##\cos^2(y)## and use ##\dfrac{d}{dy}\tan(y)=\dfrac{1}{\cos^2(y)}## and substitute ##u = \tan(y)##.
 
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