Are the solutions to first order ODE's the same or different for x=a?

[mhill]

Let be the first order ODE's

y'(x)g(x)=0 and y'(x)g(x)=\delta (x-a)

except when x=a the two equations are equal , however the solutions are very different

y(x)=C and y(x)= C+ \int dx \frac{\delta (x-a)}{g(x)}

or using the properties of Dirac delta y(x)=C+\frac{1}{g(a)}

the second equation depends on the form of g(x) whereas the first does not, however except at the point x=a the 2 ODE's are completely equal.

 

[HallsofIvy]

Why are you saying the two solutions are different? You should be writing C for one and, say, C' for the other- the two constants are not necessarily the same. In fact, all you are saying is that C= C'+ 1/g(a). Which is perfectly reasonable since 1/g(a) is itself a constant.