Fixed Points of ODE: Clarifying Conditions

Click For Summary

Discussion Overview

The discussion revolves around the conditions under which a given ordinary differential equation (ODE) has fixed points. Specifically, it examines the implications of the parameters involved in the ODE and the behavior of the function q(ψ).

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions the generality of the condition for the existence of fixed points, suggesting that it may not hold when q(ψ) is always positive.
  • Another participant proposes that the intermediate value property, assuming q is continuous, could support the existence of fixed points under certain conditions.
  • A third participant acknowledges the contributions of the previous posts, indicating a level of agreement with the points raised.

Areas of Agreement / Disagreement

Participants express differing views on the general applicability of the fixed point condition, indicating that multiple competing perspectives remain unresolved.

Contextual Notes

The discussion does not clarify the specific assumptions regarding the function q(ψ) or the nature of the parameters ν and ε, which may affect the conclusions drawn.

Apteronotus
Messages
201
Reaction score
0
In a book on synchronization it is stated that given the ODE

[tex]\frac{d\psi}{dt}=-\nu+\epsilon q(\psi)[/tex]

there is at least one pair of fixed points if

[tex]\epsilon q_{min}<\nu<\epsilon q_{max}[/tex]

were [tex]q_{min}, q_{max}[/tex] are the min and max values of [tex]q(\psi)[/tex] respectively.

While this could be true under particular circumstances (ie. when [tex]q_{min}<0, q_{max}>0[/tex]), I don't see how it could hold in general; such as the case when [tex]q(\psi)>0[/tex].

Can anyone shed some light on this?

Thanks in advance.
 
Physics news on Phys.org
Just think about this...

[tex] 0 = -\nu+\epsilon q(\psi)[/tex]
 
Assuming that q is continuous, the "intermediate value property" gives the answer.
 
Yes, of course! Thank you both.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K