Fixed Points of ODE: Clarifying Conditions

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 4K views
Apteronotus
Messages
201
Reaction score
0
In a book on synchronization it is stated that given the ODE

[tex]\frac{d\psi}{dt}=-\nu+\epsilon q(\psi)[/tex]

there is at least one pair of fixed points if

[tex]\epsilon q_{min}<\nu<\epsilon q_{max}[/tex]

were [tex]q_{min}, q_{max}[/tex] are the min and max values of [tex]q(\psi)[/tex] respectively.

While this could be true under particular circumstances (ie. when [tex]q_{min}<0, q_{max}>0[/tex]), I don't see how it could hold in general; such as the case when [tex]q(\psi)>0[/tex].

Can anyone shed some light on this?

Thanks in advance.
 
Physics news on Phys.org
Just think about this...

[tex] 0 = -\nu+\epsilon q(\psi)[/tex]
 
Yes, of course! Thank you both.