Flatcar Hoop Problem: Find Ball's Initial Velocity

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Homework Statement


A man is riding on a flatcar traveling at a constant speed of 9.10m/s. He wishes to throw a ball through a stationary hoop 4.90m above the height of his hands in such a manner that the ball will move horizontally as it passes through the hoop. He throws the ball with a speed of 10.8m/s with respect to himself. What must the vertical component of the initial velocity of the ball be?


Homework Equations


y=y0+v0t+1/2gt^2
y=4.9?? ..not sure if that's right
y0=0
g=9.8

The Attempt at a Solution


i am pretty sure y=4.9
using this i solved t=v0/g
then i plugged what i had into the relevant equation
and i got v0=5.65 which is way off

please help! thanks!
 
on Phys.org
Very awkward stated question but w/e.

What is the speed the vertical component when it only has a horizontal velocity?
 
i didn't write the question. it is very awkwardly stated though. would it be 0 since there is only horizontal direction?
 
Ok then just think about it like how much velocity you need to throw a ball 4.9m. Since the horizontal doesn't matter.

You might want to write down the question exactly.