1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Fluid Dynamics Question(not too difficult)

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data
    The spout heights for a container are 10 cm, 20cm, 30cm, and 40cm. The water level is maintained at a 45 cm height by an outside supply. Which water steam has the greatest range relative to the base of the container.
    ---
    I know that the one at 20cm is the greatest range already. I want to find out the actual range though.


    2. Relevant equations
    V=radical(2gh)



    3. The attempt at a solution

    For 20 cm: V=radical(2gh)
    V=radical(2*9.81*.25m)
    V=2.215m/s
    So I have the velocity but I am confused about how to find the range. Which formula do I use and what values go where?

    Do I use: Vfinal^2 - Vinitial^2=2aS, with S being distance
    OR
    Sfinal=1/2aT^2+ViT+Si with T=time and S=distance
     
  2. jcsd
  3. Mar 29, 2009 #2
    UPDATE: Figured out the answer to my question, thanks :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Fluid Dynamics Question(not too difficult)
Loading...