The focal length of a biconvex lens submerged in water can be calculated using the lensmaker's equation: 1/f = (n-1)(1/R1 - 1/R2). For a lens with a radius of curvature of 15 cm and a refractive index of water at 1.33, the correct focal length is derived by substituting the values into the equation. The correct calculation yields a focal length of approximately 0.44 m when properly applying the refractive index of the lens material and the surrounding medium.
PREREQUISITESStudents studying optics, physics educators, and anyone interested in understanding the behavior of lenses in different mediums.
Gauss M.D. said:Homework Statement
A biconvex lens with radius of curvature 15 cm has a focal length of 15 cm in air. What is its focal length if it is submerged in water (n=1.33)?
Homework Equations
1/f = (n-1)(1/R1 - 1/R2)
The Attempt at a Solution
1/f = 1/0.15 = (n-1)(2/0.15)
Solving for n gives n = 1.5
So the new equation will be:
1/f = (1.5 - 1.33)(2/0.15) = 2.27