Focal Length Calculation for a Converging Meniscus Lens

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SUMMARY

The focal length of a converging meniscus lens with an index of refraction of 1.55 and radii of curvature of 6.00 cm and 11.0 cm, filled with carbon tetrachloride (n = 1.46), can be calculated using the lens maker's equation. The correct application of the formula is crucial, as an incorrect interpretation of the radii or the refractive indices can lead to erroneous results. The initial calculation yielding 214 cm was incorrect due to a misapplication of the lens maker's equation. Properly applying the equation will yield the accurate focal length for the lens combination.

PREREQUISITES
  • Understanding of lens maker's equation
  • Knowledge of refractive indices
  • Familiarity with radii of curvature
  • Basic optics principles
NEXT STEPS
  • Review the lens maker's equation in detail
  • Calculate focal lengths for different lens types
  • Explore the effects of different refractive indices on lens performance
  • Study practical applications of converging lenses in optical systems
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Optics students, optical engineers, and anyone involved in designing or analyzing lens systems will benefit from this discussion.

Punkyc7
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A converging meniscus lens has an index of refraction of 1.55 and radii of curvature for its surfaces of 6.00 cm and 11.0 cm. The concave surface is placed upward and filled with carbon tetrachloride which has n = 1.46. What is the focal length of the glass combination?

So I tried using the lens makers equation and got
1/f=((1.55/.146)-1)(1/6-1/11)
took the inverse and got 214 cm, which is wrong, so I am wondering were I went wrong at.
 
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Punkyc7 said:
radii of curvature for its surfaces of 6.00 cm and 11.0 cm.

What?
 

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