Foorier series from haar function

[nhrock3]

http://mathworld.wolfram.com/HaarFunction.html
$$f(x)= {1, 0<=x<3/4}$$
$$f(x)= {-1, 3/4<=x<=1}$$
calculate the foorier function with haar group
here is the solution:
$$L_0=\phi_{0,-1}(x)=1\\$$
$$L_1=\phi_{0,0}(x)=\begin{Bmatrix}1,0\leq x\leq 0.5<br /> \\ <br /> -1,-0.5\leq x\leq 1<br /> end{Bmatrix}\\$$
i don't know why i have latex error here the code is
L_1=\phi_{0,0}(x)=\begin{Bmatrix}1,0\leq x\leq 0.5
\\
-1,-0.5\leq x\leq 1
end{Bmatrix}\\
$$aL_0+bL_1\\$$
$$L_2=\phi{0,1}(x)\\$$
$$L_3=\phi{1,1}(x)\\$$
$$f=0.75\phi_{0,-1}(x)+1/4\phi_{0,0}(x)+1/2sqrtof2\phi_{1,1}(x)\\$$
$$<f,e_0>=\int_{0}^{1}fe_0dx$$

 

[Mark44]

That's Fourier...

http://mathworld.wolfram.com/HaarFunction.html
$$f(x)= {1, 0<=x<3/4}$$
$$f(x)= {1, 3/4<=x<=1}$$

Is there a typo above? Otherwise, why not say that f(x) = 1, 0 <= x <= 1?

Also, I fixed your LaTeX below.

calculate the foorier function with haar group
here is the solution:
$$L_0=\phi_{0,-1}(x)=1\\$$
$$L_1=\phi_{0,0}(x)=\begin{Bmatrix}1,0\leq x\leq 0.5<br /> \\ <br /> -1,-0.5\leq x\leq 1<br /> \end{Bmatrix}\\$$
i don't know why i have latex error here the code is
L_1=\phi_{0,0}(x)=\begin{Bmatrix}1,0\leq x\leq 0.5
\\
-1,-0.5\leq x\leq 1
\end{Bmatrix}\\
$$aL_0+bL_1\\$$

What is the above supposed to be?

$$L_2=\phi{0,1}(x)\\$$
$$L_3=\phi{1,1}(x)\\$$
$$f=0.75\phi_{0,-1}(x)+1/4\phi_{0,0}(x)+1/2\sqrt{2\phi_{1,1}(x)}\\$$
$$<f,e_0>=\int_{0}^{1}fe_0dx$$

 

[nhrock3]

i have changed the function
there was a mistake