I For fun: How fast would an open-front CRT kill an average human? [A?]

  • I
  • Thread starter Thread starter DynV
  • Start date Start date
AI Thread Summary
Cutting out the front of a CRT would not kill an average adult human due to the low beam current of less than 100 microamperes. The CRT requires a vacuum to function, and there is not enough vacuum volume to alter the room's air pressure significantly. Blood would not boil unless the room was evacuated to a vacuum, which is not the case in this scenario. The discussion concluded with a humorous note, emphasizing the lighthearted nature of the topic. Overall, the CRT's design prevents it from being lethal in the described conditions.
DynV
Messages
35
Reaction score
4
The following in only for fun: If one would cut out the front of a CRT, how fast would it kill an average adult human? If the room needs to be filled with a gas, imagine the person wore a diving mask, if the room needed to be filled with acid, imagine there's some kind of protective gel or deep sea suit that would keep the victim alive (until the beam killed him/her), as long as it's not ridiculously expensive (eg 1M$). I suspect this might be an advanced topic, but I was conservative and marked it as intermediate, feel free to change it.

Happy dicking around
 
  • Skeptical
Likes PeroK
Physics news on Phys.org
Ask a silly question, get a silly answer.
The CRT would not kill you. The beam current is less than 100 uA, to continue functioning, the CRT would need to maintain a vacuum.

There is insufficient volume of vacuum in a CRT, to change the air pressure in the room.

Your blood would not boil, unless you evacuated the room to a vacuum, because you felt sorry for the electrons in the beam.
 
  • Haha
Likes berkeman
Baluncore said:
our blood would not boil
My blood is boiling now.
 
  • Like
Likes berkeman
Good reply by @Baluncore so the thread is done now.
 

Thread 'The Effect of Linear and Rotational Motion on Measured Weight'

Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
View full post »

Thread 'Coulomb gauge implies instantaneous radial electric field?'

Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
View full post »
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'

Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'

I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8 and stuck at some statements. It's little bit confused. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. Solution : The surface bound charge on the ##xy## plane is of opposite sign to ##q##, so the force will be...
View full post »

Hot Threads

Recent Insights

Back
Top