For How Large an 'n' can the Carmichael Function of n be 2?

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SUMMARY

The largest integer n for which the Carmichael function λ(n) equals 2 is definitively 24. This conclusion arises from the requirement that for any prime p not dividing n, the condition p² ≡ 1 mod(n) must hold, necessitating that n be of the form 6a. Additionally, all primes p less than or equal to √n must be included in n, leading to the conclusion that no primes greater than 5 satisfy this condition. The discussion emphasizes the importance of understanding number theory concepts to grasp these findings.

PREREQUISITES
  • Understanding of the Carmichael function λ(n)
  • Familiarity with modular arithmetic, specifically p² ≡ 1 mod(n)
  • Knowledge of prime factorization and properties of primes
  • Basic concepts in number theory
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  • Research the properties and applications of the Carmichael function λ(n)
  • Study modular arithmetic and its implications in number theory
  • Explore prime factorization techniques and their relevance to λ(n)
  • Investigate the relationship between Carmichael numbers and composite numbers
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This discussion is beneficial for mathematicians, number theorists, and students interested in advanced number theory, particularly those exploring properties of the Carmichael function and its implications in modular arithmetic.

patrickbotros
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What is the largest n such that λ(n)=2? Is there such a bound? This isn't a homework question. I'm just interested.
 
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If ##p## is not in ##n## than ##(p,n)=1 ##.
Therefore for ##p^2\equiv 1mod(n)## to hold ##n=6a## since all ##p## other than 2 and 3 are of the form ##6b\pm 1##
Also all ##p\leq \sqrt{n}## must be in ##n## since otherwise ##p^2<n##.
so we need a ##p\sharp## such that ##p_{c+1}>\sqrt{p\sharp}##.
It's easy to see that this does not hold for ##p>5##.
Therefore the answer is 24.
[EDIT:-##p\sharp=p_1\times p_2 \times p_3\times...\times p_c##.]
 
Did I scare you off ? I assumed you were familiar with some number theory terminology. If you have any questions, please ask.
 

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