Force and Power Required to Lift an Elevator Car

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Homework Help Overview

The discussion revolves around calculating the force and power required to lift an elevator car, focusing on the dynamics involved in overcoming gravitational force and producing upward acceleration. The subject area includes concepts from mechanics, specifically force, power, and motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between force, power, and velocity, questioning the correct application of formulas. There is discussion on whether to use net force or additional force to calculate power, and participants express uncertainty about the definitions of terms like Fadditional.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning each other's reasoning. Some guidance has been offered regarding the need to calculate the force required for upward acceleration, but there is no explicit consensus on the definitions or methods being used.

Contextual Notes

Participants are navigating through the implications of gravitational force and additional forces needed for acceleration, with some expressing uncertainty about the information provided and its application in calculations.

Lori
upload_2017-11-7_19-52-15.png

Homework Equations



P = W*V
Fnet = ma
V = 3.0 m/s
W = 29.9[/B]

The Attempt at a Solution


I think i got this wrong, but I want you to check if my answer is right :(

Heres what i did:

So,

P = force * velocity
P =force*3.0 m/s

force = force due to gravity + acceleration (net force) is F = ma = 29.9??

P = (29.9*3) = 89.6 kW
 

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Lori said:
force = force due to gravity + acceleration
Yes
Lori said:
= 29.9??
Isn't that just the given mg?
 
haruspex said:
Yes

Isn't that just the given mg?
Yeah! That's why I'm unsure of my answer :*(
 
Lori said:
Yeah! That's why I'm unsure of my answer :*(
So what additional force is required to produce the acceleration?
 
haruspex said:
So what additional force is required to produce the acceleration?

Would it be Faddition - 29.9 = m*a where m = 29.9/9.81
so Fadditional = 32.94

Do i use the Fnet to calculate the power or the Fadditional? I think i would have to use P = Fadditional * velocity because I'm trying to find the power of the motor specifically, so the force it should do is Fadditional right? I get the answer 98.8 which is one of the answers!
 
Lori said:
Would it be Faddition - 29.9 = m*a where m = 29.9/9.81
so Fadditional = 32.94
Not sure how you are defining Faddition there. I intended it to mean the extra force, beyond matching gravity, needed to produce the acceleration. Is that how you are defining it? It does not seem so.
Lori said:
Do i use the Fnet to calculate the power or the Fadditional?
The motor does not understand gravity. All it "understands" are the force it exerts and the speed with which it reels in the cable.
 
First calculate force required to produce upward acceleration of 1m/s^2 then u can easily calculate power.
Lori said:
Would it be Faddition - 29.9 = m*a where m = 29.9/9.81
so Fadditional = 32.94

Do i use the Fnet to calculate the power or the Fadditional? I think i would have to use P = Fadditional * velocity because I'm trying to find the power of the motor specifically, so the force it should do is Fadditional right? I get the answer 98.8 which is one of the answers!
 
Abhishek kumar said:
First calculate force required to produce upward acceleration of 1m/s^2 then u can easily calculate power.
The force upwards is 32.95 I found, so if I multiply it by 3 will I get the power output?
 
Lori said:
The force upwards is 32.95 I found, so if I multiply it by 3 will I get the power output?
Yes.
 
  • #10
Y
Lori said:
The force upwards is 32.95 I found, so if I multiply it by 3 will I get the power output?
Yes u had done it
 

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