- #1

etown

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## Homework Statement

Two positive point charges are 4.60 cm apart. If the electric potential energy is 75.0 x 10^-6 J, what is the magnitude of the force between the two charges?

## Homework Equations

U=kq/r (1)

F=kqq/r^2 (2)

## The Attempt at a Solution

So I tried using (1) to solve for q, and then i used the value i got for q in (2). the answer is supposed to be 1.63×10−3 N, but i'm just not getting it.