What is the force exerted by a laser pulse on a target?

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SUMMARY

The discussion focuses on calculating the force exerted by a laser pulse on a target, specifically a pulse with a frequency in the visible spectrum, a duration of 5×10−15 seconds, and approximately 1019 photons. The total energy of the photons is calculated using the equation E = hc/λ, resulting in an energy of 3.6×10−19 J. The momentum change is determined using p = ħk, where k = 2π/λ, and the force is derived by dividing the total momentum by the pulse duration.

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Students in physics, particularly those studying optics and quantum mechanics, as well as researchers and engineers working with laser technology and energy transfer systems.

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Homework Statement


A target is hit by a laser pulse. The frequency of the pulse is in the visible spectrum, it has duration ##5\times 10^{−15}## s and it contains approximately ##10^{19}## photons. Estimate the force exerted by the pulse on the target, given the pulse is completely absorbed by the target.

Homework Equations

The Attempt at a Solution


I think a reasonable wavelength in the visible spectrum would be ##550##nm. I can calculate the total energy of the photons that hit the target by using ##E = \frac{hc}{\lambda}## and then multiplying by ##10^{19}##. I get ##3.6\times 10^{-19}##J, and don't know where to go from there.

Alternatively I suppose I could use force = change in momentum / change in time. Then I'd use ##p = \hbar k## where ##k = \frac{2\pi}{\lambda}##. If that's the correct approach, to get the total change in momentum I just multiply the momentum expression by ##10^{19}##, right?

Thanks for any help!
 
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That will give you the total momentum. You'll then have to convert it to a force.
 
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DrClaude said:
That will give you the total momentum. You'll then have to convert it to a force.
By dividing the total momentum by the duration of the pulse?
 
Kara386 said:
By dividing the total momentum by the duration of the pulse?
Yes.
 
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haruspex said:
Yes.
Brilliant, thanks! :)
 

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