- #1
contlee
- 9
- 0
Suppose a 70kg person is in an elevator. The acceleration of the elevator is -3m/s/s. What force would the floor exert on the person? Please show work...
Force Exerted by Floor on 70kg Person in Elevator
- Thread starter contlee
- Start date
-
- Tags
- Elevator
Click For Summary
SUMMARY
The discussion centers on calculating the force exerted by the floor on a 70kg person in an elevator accelerating downwards at -3 m/s². According to Newton's second law, the net force acting on the person can be calculated using the formula F = ma. The gravitational force acting on the person is 686 N (70kg * 9.8 m/s²), and the downward acceleration of the elevator results in a net force of 210 N acting upwards, leading to a total force exerted by the floor of 476 N (686 N - 210 N).
PREREQUISITES- Understanding of Newton's laws of motion
- Basic knowledge of force calculations
- Familiarity with gravitational force concepts
- Ability to perform vector addition of forces
- Study Newton's second law of motion in detail
- Learn about free-body diagrams for visualizing forces
- Explore the effects of different accelerations on force calculations
- Investigate real-world applications of force calculations in elevators
Physics students, engineers, and anyone interested in understanding forces in dynamic systems, particularly in relation to elevators and motion.