- #1
kristibella
- 18
- 0
1. A 220 g ball is dropped from a height of 2.2 m, bounces on a hard floor, and rebounds to a height of 1.7 m. The figure shows the impulse received from the floor.
What maximum force does the floor exert on the ball?
To find the velocity, I used vi=[tex]\sqrt{}2gh[/tex] and vf=[tex]\sqrt{}2gh[/tex]. To find the impulse, I used F= [tex]\stackrel{}{}m(vf-vi)t[/tex]
Vi = 6.57 m/s (I used 2.2m for h)
Vf = 5.77 m/s (I used 1.7 m for h)
t= .005 s
F = [tex]\stackrel{(220)(5.77-6.57)}{.005}[/tex] = -35,200
What maximum force does the floor exert on the ball?
Homework Equations
To find the velocity, I used vi=[tex]\sqrt{}2gh[/tex] and vf=[tex]\sqrt{}2gh[/tex]. To find the impulse, I used F= [tex]\stackrel{}{}m(vf-vi)t[/tex]
The Attempt at a Solution
Vi = 6.57 m/s (I used 2.2m for h)
Vf = 5.77 m/s (I used 1.7 m for h)
t= .005 s
F = [tex]\stackrel{(220)(5.77-6.57)}{.005}[/tex] = -35,200
Last edited: