1. A 220 g ball is dropped from a height of 2.2 m, bounces on a hard floor, and rebounds to a height of 1.7 m. The figure shows the impulse received from the floor.(adsbygoogle = window.adsbygoogle || []).push({});

What maximum force does the floor exert on the ball?

2. Relevant equations

To find the velocity, I used vi=[tex]\sqrt{}2gh[/tex] and vf=[tex]\sqrt{}2gh[/tex]. To find the impulse, I used F= [tex]\stackrel{}{}m(vf-vi)t[/tex]

3. The attempt at a solution

Vi = 6.57 m/s (I used 2.2m for h)

Vf = 5.77 m/s (I used 1.7 m for h)

t= .005 s

F = [tex]\stackrel{(220)(5.77-6.57)}{.005}[/tex] = -35,200

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# Homework Help: Maximum force exerted by floor?

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