Force for uniform circular motion

[jj8890]

[SOLVED] Force for uniform circular motion

Homework Statement

A 61.7 kg ice skater is moving at 3.55 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.545 m around the pole. The acceleration of gravity is 9.8 m/s^2.
a. Find the force exerted by the rope on her arms. Answer in units of kN.
b. Find the ratio of this tension to her weight.

Homework Equations

F=(mv^2)/r

The Attempt at a Solution

I got a using the above equation:
F=((61.7) * (3.55)^2)/.545
F=1426.74 N or 1.42674 kN
I know this is right for part a, I just don't understand what they are asking for part b or what equation to use. I would appreciate any help.

 

[jj8890]

Please help...I just need to figure out how I would start this. I understand now that the "tension" is the force that I calculated in (a) but I am unsure how to find the ratio of this tension to her weight (61.7 kg) i was thinking just diving 61.7/1.42674 but that does not seem right. I would greatly appreciate any help.

 

[jj8890]

Got it...thanks anyway...--->1426.74/(61.7 * 9.81)=2.3572

 

[rl.bhat]

Ratio is f/mg