Force on an object in circular motion

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Homework Help Overview

The problem involves calculating the force exerted by a string on an 18.2 kg iron ball being whirled in a horizontal circle at a rate of 1.0 revolutions per second. The context is centered around circular motion and centripetal force.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the centripetal force formula and the need to convert angular velocity to linear velocity. There are attempts to clarify the relationship between revolutions per second and radians per second, as well as the correct use of units in calculations.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about units and calculations. Some have provided guidance on converting angular frequency and ensuring the correct application of formulas, while others are verifying their calculations and discussing potential errors.

Contextual Notes

There is a focus on ensuring that the units used in the calculations are appropriate, particularly the conversion from radians per second to meters per second. Participants are also reflecting on the implications of their calculations and the values obtained.

BuBbLeS01
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Homework Statement


A hammer thrower whirls a 18.2 kg iron ball on the end of a 1.2 m string at 1.0 revolutions per second in a horizontal circle. Calculate the force in the string.


Homework Equations


F=m(v^2/r)


The Attempt at a Solution


I am not sure how to do this...
I set up a table of forces in the x and y direction...
x = T & centripetal force
y = W
I am not even sure I am starting off right.
 
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What type of force is acting through the string? (i.e. What type of motion is it causing?)
 
Since the circle is horizontal, you know that F=m(v^2/r) will be equal to the tension in the string.

Can you obtain that value from the known information?
 
No I need to get the revolutions/sec in radians/sec
 
So I multiplied 1 rev/sec by 2pi to get the velocity...
F= 18.2 kg(2pi^2/1.2) = 598.76 N
That seems high?
 
Ok, you have the velocity in radians per second, so you have the angular velocity. The formula you are using assumes that the velocity is in meters per second. So, you'll either have to convert or use the version of the formula where the angular velocity is involved. Do you know this form of the centripetal force formula?
 
Last edited:
Hmm, still missing something.

The velocity in your formula needs units of m/s, not radian/s. You're almost there, can you change it to that?
 
I think the formula is v= wr to get it into m/s so that would be 598.76rad/s * 1.2 m = 718.51 m/s
 
BuBbLeS01 said:
I think the formula is v= wr to get it into m/s so that would be 598.76rad/s * 1.2 m = 718.51 m/s

This is not correct.

Check you math when computing the angular frequency.

Remember:

[tex]\omega = 2 \pi f[/tex]
 
Last edited:
  • #10
ok if I am doing this right I am getting a huge number of 7818780.67 N
 
  • #11
I think I did something wrong maybe its supposed to be...
w=2pi * f = 6.28 rad/s
v=wr
6.28 rad/s * 1.2 m = 7.54 m/s
 
  • #12
BuBbLeS01 said:
I think I did something wrong maybe its supposed to be...
w=2pi * f = 6.28 rad/s
v=wr
6.28 rad/s * 1.2 m = 7.54 m/s

Yes this is correct. Sorry, I apparently didn't notice the error either.
 
  • #13
thanks!
 
  • #14
BuBbLeS01 said:
thanks!

No problem!
 

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