The discussion centers on calculating the force acting on a 20cm wire carrying a current of 10A in a magnetic field of 0.3T, positioned at a 40-degree angle to the field. The formula used is F = LIB sin(θ), where L is the length of the wire, I is the current, B is the magnetic field strength, and θ is the angle. The calculated force is 0.35N, while the textbook states it as 0.39N. The discrepancy is attributed to potential miscalculations in determining sin(40°), which equals approximately 0.643.
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uzair_ha91 said:Homework Statement
A 20cm wire carrying a current of 10A is placed in a uniform
magnetic field of 0.3T. If the wire makes an angle of 40 degrees with
the direction of magnetic field, find the force acting on the wire.
Homework Equations
F=LIB sin<theta>
The Attempt at a Solution
I got the answer:: 0.35, but in the textbook, the answer written at the back is 0.39...which one's correct??