Forces involved in circular motion

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In circular motion, a ball on a string experiences centripetal acceleration, with tension in the string acting as the centripetal force directed towards the center of the circle. According to Newton's third law, for every action, there is an equal and opposite reaction, meaning that if the string exerts a force on the ball, the ball exerts an equal and opposite force on the string. The confusion often arises with the concept of centrifugal force, which is not a true force but a fictitious one used in rotating frames. The key takeaway is that the reaction force to the tension in the string is the force exerted by the ball on the string. Understanding these forces is crucial for mastering the principles of circular motion.
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Homework Statement


hey, i was looking at an explanation in a textbook where it says a ball on the end of a string is swung horizontally in circular motion. There is a centripetal acceleration therefore tension acts as the centripetal force and acts along the radius of the circular path. What i want to know is that Newtons third law states that every action has an opposite and equal reaction. So what is the reaction force of the tension acting on the string?


Homework Equations



F=mv^2/r

The Attempt at a Solution


I can't seem to be able to figure out what it is but i think mass would not be the reaction force because mass is a scaler and has no direction. The other explanation would be centrifugal force but isn't centrifugal force a reaction force of centripetal force? which is what I am trying to find? This is why I am a little confused.
 
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Forget centrifugal force--that's a special "fictitious" force used when analyzing things from a rotating frame. (You probably won't use that until you get to a more advanced class.)

Instead, just use the most basic form of Newton's 3rd law: If A exerts a force on B, then B exerts an equal and opposite force on A. If the string pulls the ball, the ball pulls the string.
 
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