Circular motion/ speed increases at a constant rate

Click For Summary

Homework Help Overview

The discussion revolves around an object moving in a circular path with a speed that increases at a constant rate. Participants are exploring the implications of this scenario on the forces acting on the object, particularly focusing on centripetal and tangential components of acceleration and force.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the nature of forces in non-uniform circular motion, particularly the relationship between tangential and radial components of acceleration and force. There is discussion about the implications of increasing speed on these components and the confusion surrounding the definitions of acceleration in this context.

Discussion Status

Some participants have provided insights into the nature of acceleration in circular motion, while others express confusion regarding the relationship between tangential and radial forces. The conversation is ongoing, with various interpretations being explored without a clear consensus.

Contextual Notes

Participants are grappling with the concepts of non-uniform circular motion and the associated forces, indicating a need for further clarification on the definitions and relationships involved. There is also mention of prior learning that may not align with the current problem context.

YMMMA
Messages
156
Reaction score
10

Homework Statement


If an object moves in a circular path with a speed that increases at a constant rate, which of the following can be concluded?

(A) The radial component of the force acting on the object is zero.
(B) The net force acting on the object is zero.
(C) The net force acting on the object is directed toward the center of the circle.
(D) The net force acting on the object has a radial component and a tangential component that are equal at all times
(E) The tangential component of the force acting on the object is constant.

Homework Equations


Centripetal force = mass times centripetal acceleration.

The Attempt at a Solution


I[/B] learned that speed is constant in circular motion, so does its centripetal force and acceleration. Velocity is tanget to the force and acceleration and that’s why it accelerates while maintaining its speed. But for this situation why and how the speed is increasing. I have no idea.
 
Physics news on Phys.org
YMMMA said:
I learned that speed is constant in circular motion
You shouldn't have. Why 'invent' angular acceleration if what you learned is the case ?

Again, your relevant equations don't cut it. Think of something better.
 
YMMMA said:
Velocity is tanget to the force and acceleration and that’s why it accelerates while maintaining its speed.
I assume you mean that if the speed is constant then velocity is normal to the force and to the acceleration, and that is why it can have a nonzero acceleration at constant speed.
Anyway, as BvU notes, you are told the speed is not constant here.
 
  • Like
Likes   Reactions: YMMMA
I think I will understand it if I looked for the topic of rotational dynamics. I will make sure I know them well before coming back to that question.
 
So yeah, I looked for this lesson, non-uniform circular motion, and got that because it speeds up it has a radial and tangential acceleration. Thus, It has a net acceleration, and for the force it also has a radial, tangential and a net force. That means I have to choose between E and D. I am confused actually. If it is increasing at a constant rate, that means thant the tangential acceleration is constant and also its tangential force. What about the radial one? Is it constant, too? But I would choose E.
 
YMMMA said:
What about the radial one?
What equation do you know regarding radial (centripetal) acceleration?
 
It is velocity squared divided by the radius. But the velocity is increasing, so it should increase as well. Right?
 
YMMMA said:
It is velocity squared divided by the radius. But the velocity is increasing, so it should increase as well. Right?
Right.
 
  • Like
Likes   Reactions: YMMMA

Similar threads

Replies
55
Views
3K
Replies
11
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
916
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
4K