Forces involved in circular motion

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SUMMARY

The discussion centers on the forces involved in circular motion, specifically the relationship between tension in a string and centripetal force. It is established that tension acts as the centripetal force, directing towards the center of the circular path. According to Newton's Third Law, the reaction force to the tension in the string is the force exerted by the ball on the string, which is equal in magnitude and opposite in direction. The concept of centrifugal force is clarified as a fictitious force not applicable in this context.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Basic knowledge of circular motion dynamics
  • Familiarity with centripetal acceleration and its formula, F=mv²/r
  • Concept of action-reaction pairs in physics
NEXT STEPS
  • Study the implications of Newton's Third Law in various physical scenarios
  • Explore the concept of centripetal acceleration in different contexts, such as roller coasters
  • Learn about fictitious forces and their applications in rotating reference frames
  • Investigate real-world applications of circular motion, such as satellites and planetary orbits
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, educators teaching circular motion concepts, and anyone interested in the practical applications of Newton's Laws.

scottnobles
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Homework Statement


hey, i was looking at an explanation in a textbook where it says a ball on the end of a string is swung horizontally in circular motion. There is a centripetal acceleration therefore tension acts as the centripetal force and acts along the radius of the circular path. What i want to know is that Newtons third law states that every action has an opposite and equal reaction. So what is the reaction force of the tension acting on the string?


Homework Equations



F=mv^2/r

The Attempt at a Solution


I can't seem to be able to figure out what it is but i think mass would not be the reaction force because mass is a scaler and has no direction. The other explanation would be centrifugal force but isn't centrifugal force a reaction force of centripetal force? which is what I am trying to find? This is why I am a little confused.
 
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Forget centrifugal force--that's a special "fictitious" force used when analyzing things from a rotating frame. (You probably won't use that until you get to a more advanced class.)

Instead, just use the most basic form of Newton's 3rd law: If A exerts a force on B, then B exerts an equal and opposite force on A. If the string pulls the ball, the ball pulls the string.
 

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