Four-Dimensional Vector in Special Relativity

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
zhangyang
Messages
58
Reaction score
0
About momentum-energy vector ,we have :

[itex]\vec{P}[/itex]=([itex]\vec{p}[/itex],i[itex]\frac{E}{c}[/itex])

and four dimentianal wave vector :

[itex]\vec{K}[/itex]=([itex]\vec{k}[/itex],i[itex]\frac{\omega}{c}[/itex])

They also satisfy the ralation :

[itex]\vec{P}[/itex]=[itex]\frac{h}{2\pi}[/itex][itex]\vec{K}[/itex],

because E=[itex]\frac{h}{2\pi}[/itex][itex]\omega[/itex].

It is interesting.
 
Last edited:
Physics news on Phys.org
FYI: very few people use the imaginary basis for time anymore, when speaking of 4-vectors. Instead of a (+,+,+,+) metric with one imaginary basis, a mixed signature metric is used.
 
ds[itex]^{2}[/itex]=x[itex]^{2}[/itex]+y[itex]^{2}[/itex]+z[itex]^{2}[/itex]-c[itex]^{2}[/itex]t[itex]^{2}[/itex]

In the four dimensional space-time vector,the concept of time has been bent,because time has the meaning of evolution and irreversibility.So it can't convert into space freely.