- #1

- 180

- 8

Hey there!

I'm trying to calculate the Fourier Series for sin

For a

Since sin

Now, for a

http://www.wolframalpha.com/...

Since a

I'm trying to calculate the Fourier Series for sin

^{2}x on [-π, π]For a

_{0}I found 1/2. (By determining the average value of the function on the interval)Since sin

^{2}x is even, I know that b_{n}= 0.Now, for a

_{n}.. The following link shows the integral I used to try to evaluate a_{n}.http://www.wolframalpha.com/...

Since a

_{n}and b_{n}are both coming out to be zero, doesn't this imply that sin^{2}x = a_{0}= 1/2? Will someone please show me where I am going wrong? Can't find anything online about this. Everyone just always uses the sin^{2}identity and calls it good.
Last edited: