Fourier transform and steady state solution?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 7K views
hanson
Messages
312
Reaction score
0
Hi all!
I am asking about a question about Fourier transform.
I can only roughly remember things about Fourier transform.
I am told that Fourier transform gives the steady state solution, is it?
I can hardly relate these two concepts.
Can someone try to explain?
Many thanks.
 
Physics news on Phys.org
May be http://users.rowan.edu/~polikar/WAVELETS/WTpart1.html" might give a clue in understanding.

Let say that we have a signal
[tex]f(t) = cos(20\pi t) + cos(50\pi t) + cos(100\pi t) + cos(200\pi t)[/tex]
which is a stationary signal (steady state I presume). The Fourier transform of this signal will identify that this signal has frequencies of 10, 25, 50, and 100 Hz at any given time instant.
Next consider another signal of period 1s,

[tex]g(t)=\left\{\begin{array}{cc}cos(200\pi t),&\mbox{ if }<br /> 0\leq t < 0.3 \\<br /> cos(100\pi t), & \mbox{ if } 0.3 \leq t < 0.6 \\<br /> cos(50\pi t), & \mbox{ if } 0.6 \leq t < 0.8 \\<br /> cos(20\pi t), & \mbox{ if } 0.8 \leq t < 1 <br /> \end{array}\right[/tex]

Signal g(t) is a transient signal. But the Fourier transforms of g(t) and f(t) are almost identical. So given some coeffients, the Fourier transform will identify the signal as f(t) the stationary signal.
To analyse the second signal we use other transform e.g. wavelet transform.

What am I writing here?
 
Last edited by a moderator: